Until this point, you have been dealing with decibels as the ratio of two powers, that is,
| dB = 10·log10(P1/P2) |
With decibels being a ratio of two powers, what is the meaning of decibels for absolute power?
The key to looking at absolute power with decibels is to use P2 as a reference power. To make this more explicit, let's use P2 = 1 W as a reference power. We can then say that
| Power (dBW) = 10·log10(P1/1 W) |
| Power (dBm) = 10·log10(P1/1 mW) |
Note that the power P1 must be in the same units as the reference power, exactly as with other decibel problems.
Let's try some problems.